Friday 10 April 2009

PROJECT EULER #1

Link to Project Euler problem 1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.

Not much to say about this one..


using System;

namespace ProjectEuler
{
class Program
{
static void Main(string[] args)
{
//Problem 1
int sum=0;
for (int i = 1; i < 1000;i++ )
{
sum += i%3 == 0 i%5 == 0 ? i : 0;
}
Console.WriteLine("{0}",sum);
}
}
}

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