145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145.
Find the sum of all numbers which are equal to the sum of the factorial of their digits.
Note: as 1! = 1 and 2! = 2 are not sums they are not  included.
using System;
namespace project_euler
{
 class Program
 {
     static void Main()
     {
         //Problem 34
         DateTime start = DateTime.Now;
         long total = 0;
         for (int i = 3; i < 50000; i++)
         {
             long sum = 0;
             string s = i.ToString();
             for (int j = 0; j < s.Length; j++)
                 sum += Factorial(int.Parse(s[j].ToString()));
             if (sum == i)
                 total += sum;
         }
         Console.WriteLine(total);
         TimeSpan time = DateTime.Now - start;
         Console.WriteLine("This took {0}", time);
         Console.ReadKey();
     }
     public static int Factorial(int n)
     {
         int number = n;
         if (n == 0) return 1;
         for (int i = 1; i < n; i++)
             number *= i;
         return number;
     }
 }
}

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