PROJECT EULER #26

Link to Project Euler problem 26

A unit fraction contains 1 in the numerator. The decimal representation of the unit fractions with denominators 2 to 10 are given:

1/2	=	0.5
1/3	=	0.(3)
1/4	=	0.25
1/5	=	0.2
1/6	=	0.1(6)
1/7	=	0.(142857)
1/8	=	0.125
1/9	=	0.(1)
1/10	=	0.1

Where 0.1(6) means 0.166666..., and has a 1-digit recurring cycle. It can be seen that ¹/₇ has a 6-digit recurring cycle.

Find the value of d < 1000 for which 1/ d contains the longest recurring cycle in its decimal fraction part.

using System;
using System.Collections.Generic;

namespace project_euler
{
   class Program
   {
       static void Main()
       {
           //Problem 26
           DateTime start = DateTime.Now;
           int maxLength = 0, result=0;
           for( int i=1; i<1000; i++ )
           {
           int length = LengthOfCycle(i);
               if( length > maxLength )
               {
                   result = i;
                   maxLength = length;
               }
           }
           Console.WriteLine(result);
           TimeSpan time = DateTime.Now - start;
           Console.WriteLine("This took {0}", time);
           Console.ReadKey();
       }
       public static int LengthOfCycle(int n)
       {
           var quotients = new List<int>(1000){0};
           var remainders = new List<int>(1000) {1};
           for (int i = 1; i < 1000; i++)
           {
               quotients.Add(remainders[i - 1]*10/n);
               remainders.Add(remainders[i - 1]*10 - quotients[i]*n);
               for (int j = 0; j < i; j++)
                   if (quotients[j] == quotients[i] && remainders[j] == remainders[i])
                       return i - j;
           }
           return -1;
       }
   }
}